প্রদত্ত রাশি $(8-3x)^{-1/3} = 8^{-1/3} (1 - \frac{3x}{8})^{-1/3} = \frac{1}{2} (1 - \frac{3x}{8})^{-1/3}$। দ্বিপদী বিস্তৃতি $(1-z)^{-n} = 1 + nz + \frac{n(n+1)}{2!}z^2 + \frac{n(n+1)(n+2)}{3!}z^3 + \dots$ ব্যবহার করে পাই, $$\begin{aligned} (1 - \frac{3x}{8})^{-1/3} &= 1 + \frac{1}{3}(\frac{3x}{8}) + \frac{\frac{1}{3}(\frac{1}{3}+1)}{2!}(\frac{3x}{8})^2 + \frac{\frac{1}{3}(\frac{1}{3}+1)(\frac{1}{3}+2)}{3!}(\frac{3x}{8})^3 + \dots \\ &= 1 + \frac{x}{8} + \frac{\frac{1}{3} \cdot \frac{4}{3}}{2}(\frac{9x^2}{64}) + \frac{\frac{1}{3} \cdot \frac{4}{3} \cdot \frac{7}{3}}{6}(\frac{27x^3}{512}) + \dots \end{aligned}$$ $x^3$ এর সহগ হবে, $$\frac{1}{2} \cdot [ \frac{1 \cdot 4 \cdot 7}{3^3 \cdot 6} \cdot \frac{27}{512} ] = \frac{1}{2} \cdot [ \frac{28}{162} \cdot \frac{27}{512} ] = \frac{1}{2} \cdot [ \frac{28}{6 \cdot 512} ] = \frac{14}{3072} = \frac{7}{1536}$$ নির্ণেয় সহগ $\frac{7}{1536}$।