To find the molarity of the mixture, we use the formula for mixing solutions of the same solute: $$ \begin{aligned} V_1 M_1 + V_2 M_2 &= (V_1 + V_2) M \end{aligned} $$ Given that the volumes are equal, let $V_1 = V_2 = V$. Substituting the values $M_1 = 2.0 \text{ M}$ and $M_2 = 0.5 \text{ M}$: $$ \begin{aligned} V(2.0) + V(0.5) &= (V + V) M \\ V(2.0 + 0.5) &= 2V M \\ 2.5V &= 2V M \\ M &= \frac{2.5}{2} \\ M &= 1.25 \text{ M} \end{aligned} $$ Thus, the molarity of the resulting solution is $1.25 \text{ M}$.