Given $0 < x < 1$. Let $x = \frac{1}{2}$. Then: $$ \begin{aligned} \frac{1}{x} &= \frac{1}{1/2} = 2 \\ \frac{1}{x^2} &= \frac{1}{(1/2)^2} = \frac{1}{1/4} = 4 \\ x^2 &= (1/2)^2 = 1/4 = 0.25 \\ x^3 &= (1/2)^3 = 1/8 = 0.125 \end{aligned} $$ Comparing the values, $\frac{1}{x^2}$ is the largest.