Given that, Rest mass of the person, $m_0 = 100 \text{ kg}$ Relativistic mass of the person, $m = 101 \text{ kg}$ Speed of light, $c = 3 \times 10^8 \text{ m/s}$ We know the formula for relativistic mass is: $$ \begin{aligned} m &= \frac{m_0}{\sqrt{1 - \frac{v^2}{c^2}}} \end{aligned} $$ Squaring both sides and rearranging to solve for $v$: $$ \begin{aligned} m^2 &= \frac{m_0^2}{1 - \frac{v^2}{c^2}} \\ 1 - \frac{v^2}{c^2} &= \frac{m_0^2}{m^2} \\ \frac{v^2}{c^2} &= 1 - \left( \frac{m_0}{m} \right)^2 \\ v &= c \sqrt{1 - \left( \frac{m_0}{m} \right)^2} \end{aligned} $$ Substituting the values: $$ \begin{aligned} v &= 3 \times 10^8 \times \sqrt{1 - \left( \frac{100}{101} \right)^2} \\ v &= 3 \times 10^8 \times \sqrt{1 - 0.980297} \\ v &= 3 \times 10^8 \times \sqrt{0.019703} \\ v &= 3 \times 10^8 \times 0.140367 \\ v &\approx 4.211 \times 10^7 \text{ m/s} \end{aligned} $$ Thus, the velocity of the rocket is approximately $4.21 \times 10^7 \text{ m/s}$.